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1.           A particle is projected with velocity${\upsilon _0}$ along$x - axis$ $x - axis$. The deceleration on the particle is proportional to the square of the distance from the origin i.e $a = \alpha {x^2}.$.$a = \alpha {x^2}.$, The distance at which the particle stops is

(a)$\sqrt {\frac{{3{\upsilon _0}}}{{2\alpha }}} $                                    (b)${\left( {\frac{{3{v_o}}}{{2\alpha }}} \right)^{\frac{1}{3}}}$  



(c)$\sqrt {\frac{{3\upsilon {}_0^2}}{{2\alpha }}} $                                    (d)${\left( {\frac{{3\upsilon {}_0^2}}{{2\alpha }}} \right)^{\frac{1}{3}}}$  

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